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IP Subnetting Step #5: Determining Host Addresses For Each Subnet
(Page 2 of 3)
Class B Host Address Determination Example
We can do the same thing for our
Class B network, naturally. The address of that network is 126.96.36.199.
Now, say we want to define the hosts that go in subnet #13. We substitute
13 in binary (01101) for the subnet ID bits, to get the following subnet
address, shown with the subnet ID bits highlighted and the host ID bits
highlighted and underlined:
10100110 01110001 01101000
This is the subnet address 188.8.131.52.
Now, we have 11 bits of host ID, so we can have a maximum of 2,046 hosts.
The first is found by substituting 000 00000001 for the
host ID bits, to give an address of 184.108.40.206. The second
host is 220.127.116.11, and so on. The last is found by substituting
111 11111110, to give an address of 18.104.22.168. Note
that since the host ID bits extend over two octets, two octets change
as we increment the host ID, unlike our Class C example. The broadcast
address is 22.214.171.124.
Key Concept: In a subnetted network, the address of host #H within subnet number #S is found by plugging in the binary value of S for the networks subnet ID bits, and the binary value of H for subnets host ID bits.
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Version 3.0 - Version Date: September 20, 2005
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